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Question Number 62534 by peter frank last updated on 22/Jun/19
Answered by tanmay last updated on 22/Jun/19
$${bi}\:{metal}\:{changed}\:{to}\:{a}\:{shape}\:{concave}.. \\ $$$$\:\:{as}\:\:\:\smallsmile\:{and}\:{touch}\:{upper}\:.\:{point}\:{to}\:{activate} \\ $$$${A}\:...{so}\:{A}\:{is}\:{cooler} \\ $$$${and}\:{B}\:{is}\:{heater}...{i}\:{think}\:{so} \\ $$
Commented by peter frank last updated on 24/Jun/19
$${thank}\:{you} \\ $$