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Question Number 62596 by aliesam last updated on 23/Jun/19
∫sin100(x)cos100(x)dx
Answered by MJS last updated on 23/Jun/19
∫sin100xcos100xdx=∫(sinxcosx)100dx==12100∫sin1002xdx=[t=2x→dx=dt2]=12101∫sin100tdtnowuse∫sinntdt=−costsinn−1tn+n−1n∫sinn−2tdt
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