Question and Answers Forum

All Questions      Topic List

UNKNOWN Questions

Previous in All Question      Next in All Question      

Previous in UNKNOWN      Next in UNKNOWN      

Question Number 62612 by hovea cw last updated on 23/Jun/19

The number of real solutions of the equation ((9/(10)))^x = −3+x−x^2 is

Thenumberofrealsolutionsoftheequation(910)x=−3+x−x2is

Answered by tanmay last updated on 23/Jun/19

−3+x−x^2 =−x^2 +x−3 =−(x^2 −x+3) =−(x^2 −2×x×(1/2)+(1/4)−(1/4)+3) =−(x−(1/2))^2 +(1/4)−3 =−(x−(1/2))^2 −((11)/4)<0 [always −ve] but ((9/(10)))^x >0 [aleays +ve] so no real solution

−3+x−x2=−x2+x−3=−(x2−x+3)=−(x2−2×x×12+14−14+3)=−(x−12)2+14−3=−(x−12)2−114<0[always−ve]but(910)x>0[aleays+ve]sonorealsolution

Terms of Service

Privacy Policy

Contact: info@tinkutara.com