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Question Number 62624 by Jmasanja last updated on 23/Jun/19

Answered by MJS last updated on 23/Jun/19

$${\mathrm{it}}^{\prime }\mathrm{s}\mathrm{the}\mathrm{same}\mathrm{as}\mathrm{before},\mathrm{they}\mathrm{all}\mathrm{are}\mathrm{similar}$$$$P=\left(\begin{array}{c}9\cos 270°\\ 9\sin 270°\end{array}\right)Q=\left(\begin{array}{c}10\cos 45°\\ 10\sin 45°\end{array}\right)R=\left(\begin{array}{c}10\cos 135°\\ 10\sin 135°\end{array}\right)$$$$P=\left(\begin{array}{c}0\\ -9\end{array}\right)Q=\left(\begin{array}{c}5\sqrt{2}\\ 5\sqrt{2}\end{array}\right)R=\left(\begin{array}{c}-5\sqrt{2}\\ 5\sqrt{2}\end{array}\right)$$$$P+Q+R=\left(\begin{array}{c}0\\ 10\sqrt{2}-9\end{array}\right)$$

Answered by behi83417@gmail.com last updated on 23/Jun/19

$${\mathrm{R}}_{\mathrm{RQ}}=2\times 10\cos \frac{90}{2}=20\frac{\sqrt{2}}{2}=10\sqrt{2}$$$${\mathrm{R}}_{\mathrm{esultant}}=9\downarrow +10\sqrt{2}\uparrow =5.142\uparrow$$

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