Question Number 62750 by peter frank last updated on 24/Jun/19
$${An}\:{element}\:{X}\:{has}\:{RAM} \\ $$$${of}\:\mathrm{88}{g}.{when}\:{a}\:{current} \\ $$$${of}\:\mathrm{0}.\mathrm{5}{A}\:{was}\:{passed}\:{through} \\ $$$${fused}\:{chloride}\:{of}\:{X}\:{for} \\ $$$$\mathrm{32}{minutes}\:{and}\:\mathrm{10}{sec}. \\ $$$$\mathrm{0}.\mathrm{44}{g}\:{of}\:{X}\:{was}\:{deposited} \\ $$$${at}\:{the}\:{cathode} \\ $$$$\left({a}\right){number}\:{of}\:{faraday}? \\ $$$$\left({b}\right){write}\:{formular}\:{of}\: \\ $$$${X}\:{ions} \\ $$$$\left({c}\right){write}\:{the}\:{formular}\:{of}\:{OH} \\ $$
Commented by peter frank last updated on 25/Jun/19
$${t}=\mathrm{32}{min}+\mathrm{10}=\mathrm{1930} \\ $$$${I}=\mathrm{0}.\mathrm{5} \\ $$$${Q}={I}\:×{t} \\ $$$${Q}=\mathrm{0}.\mathrm{5}×\mathrm{1930}=\mathrm{965} \\ $$$$\mathrm{0}.\mathrm{44}{g}\rightarrow\mathrm{965} \\ $$$$\mathrm{88}{g}\:\rightarrow{Q} \\ $$$${Q}=\mathrm{193000}{C} \\ $$$$\mathrm{1}{F}=\mathrm{96500}{C} \\ $$$${x}=\mathrm{193000} \\ $$$$\left.{a}\right){x}=\mathrm{2}{F} \\ $$$$\left({b}\right){X}^{\mathrm{2}+} \\ $$$$\left({c}\right){X}+{OH}={X}\left({OH}\right)_{\mathrm{2}} \\ $$$$...... \\ $$