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Question Number 62844 by alphaprime last updated on 25/Jun/19

Let p(x) = ax^2  + bx + c  be such that p(x) takes real values  for real values of x and non−real values for non−real  values of x . Prove that a = 0 and find all  possible values of c.

$${Let}\:{p}\left({x}\right)\:=\:{ax}^{\mathrm{2}} \:+\:{bx}\:+\:{c}\:\:{be}\:{such}\:{that}\:{p}\left({x}\right)\:{takes}\:{real}\:{values} \\ $$$${for}\:{real}\:{values}\:{of}\:{x}\:{and}\:{non}−{real}\:{values}\:{for}\:{non}−{real} \\ $$$${values}\:{of}\:{x}\:.\:{Prove}\:{that}\:{a}\:=\:\mathrm{0}\:{and}\:{find}\:{all} \\ $$$${possible}\:{values}\:{of}\:{c}. \\ $$

Answered by ajfour last updated on 29/Sep/23

c=3 ?

$${c}=\mathrm{3}\:? \\ $$

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