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Question Number 62874 by solihin last updated on 26/Jun/19

$$\underset{x\to 0}{\lim }\frac{sin\left(6x\right)}{tan\left(5x\right)}$$$$$$$$howtosolvethisw/o{L}^{\prime }{hospital}^{\prime }srule?$$

Commented by kaivan.ahmadi last updated on 26/Jun/19

$${lim}_{x\to 0}\frac{sin6x}{6x}\times \frac{5x}{tan5x}\times \frac{6}{5}=1\times 1\times \frac{6}{5}=\frac{6}{5}$$

Commented by solihin last updated on 26/Jun/19

$$wowthx$$

Commented by mathmax by abdo last updated on 26/Jun/19

$${lim}_{x\to 0}\frac{sin\left(6x\right)}{tan\left(5x\right)}={lim}_{x\to 0}\frac{6cosx}{5(1+{tan}^2\left(5x\right))}=\frac{6}{5}$$

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