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Question Number 62889 by Tawa1 last updated on 26/Jun/19

Answered by Kunal12588 last updated on 26/Jun/19

$$\left(a\right)s=t^2-5t+6$$$$atinitialpos.t=0$$$$s\left(0\right)=6$$$$\therefore theinitialdist.ofparticlefromOis6m$$$$\left(b\right)s\left(3\right)=9-15+6=0$$$$\because motionisinstraightline$$$$distance=\mid initialpos.-finalpos.\mid$$$$=\mid 6-0\mid$$$$=6m$$

Commented by Tawa1 last updated on 26/Jun/19

$$\mathrm{God}\mathrm{bless}\mathrm{you}\mathrm{sir}$$

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