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Question Number 63121 by hovea cw last updated on 29/Jun/19

x^(1/2)  ∙ x^(1/4)  ∙ x^(1/8)  ∙ x^(1/16)  ... to ∞ is equal to

$${x}^{\mathrm{1}/\mathrm{2}} \:\centerdot\:{x}^{\mathrm{1}/\mathrm{4}} \:\centerdot\:{x}^{\mathrm{1}/\mathrm{8}} \:\centerdot\:{x}^{\mathrm{1}/\mathrm{16}} \:...\:\mathrm{to}\:\infty\:\mathrm{is}\:\mathrm{equal}\:\mathrm{to} \\ $$

Commented by Prithwish sen last updated on 29/Jun/19

thank you

$$\mathrm{thank}\:\mathrm{you} \\ $$

Commented by Prithwish sen last updated on 29/Jun/19

x^((1/2) +(1/4) +(1/8) + .....)   =x^((1/2)/(1−(1/2)))  = x  please check

$$\mathrm{x}^{\frac{\mathrm{1}}{\mathrm{2}}\:+\frac{\mathrm{1}}{\mathrm{4}}\:+\frac{\mathrm{1}}{\mathrm{8}}\:+\:.....} \\ $$$$=\mathrm{x}^{\frac{\frac{\mathrm{1}}{\mathrm{2}}}{\mathrm{1}−\frac{\mathrm{1}}{\mathrm{2}}}} \:=\:\mathrm{x} \\ $$$$\mathrm{please}\:\mathrm{check} \\ $$$$ \\ $$

Commented by hovea cw last updated on 29/Jun/19

very correct sir nice one

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