A solenoid is 40cm long,has a cross sectional area of 8.0cm^2 and is wound with 309 turns of wire that carries a current of 1.2A.The relative permeability of the iron core is 600. Compute the B for the interior point and the flux through the solenoid.


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Question Number 63124 by necx1 last updated on 29/Jun/19

$A s o l e n o i d i s 40 c m l o n g, h a s a c r o s s$ $s e c t i o n a l a r e a o f 8.0 {c m}^{2} a n d i s w o u n d$ $w i t h 309 t u r n s o f w i r e t h a t c a r r i e s a$ $c u r r e n t o f 1.2 A . T h e r e l a t i v e$ $p e r m e a b i l i t y o f t h e i r o n c o r e i s 600 .$ $C o m p u t e t h e B f o r t h e i n t e r i o r p o i n t$ $a n d t h e f l u x t h r o u g h t h e s o l e n o i d .$
Commented by necx1 last updated on 29/Jun/19

$p l e a s e h e l p$
Commented by Hope last updated on 29/Jun/19

Commented by Hope last updated on 29/Jun/19

Commented by Hope last updated on 29/Jun/19

Commented by Hope last updated on 29/Jun/19

	Answered by peter frank last updated on 30/Jun/19

	$f l u x = A (i n m e t e r)) \times B . . . . . . . (i)$ $B = μ_{m} n I$ $n = \frac{N}{L (m e t e r)} . . . . . . . . (i i)$ $μ_{r} (r e l a t i v e p e r m e a b i l i t y) = \frac{μ_{m}}{μ_{o}} . . . . . . . (i i i)$ $μ_{m} = μ_{r} \times μ_{o} (a b s o l u t e p)$
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