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Question Number 63361 by rajesh4661kumar@gamil.com last updated on 03/Jul/19

Commented by Prithwish sen last updated on 03/Jul/19

tan3A = tan(2A+A)=((tan2A+tanA)/(1−tan2AtanA))  tan3A−tan3Atan2AtanA = tan2A+tanA  tan3A−tan2A−tanA = tan3Atan2AtanA proved.

tan3A=tan(2A+A)=tan2A+tanA1tan2AtanAtan3Atan3Atan2AtanA=tan2A+tanAtan3Atan2AtanA=tan3Atan2AtanAproved.

Commented by Hope last updated on 03/Jul/19

i think tan3A−tan2A−tanA=tan3Atan2AtanA  so in question error is present..

ithinktan3Atan2AtanA=tan3Atan2AtanAsoinquestionerrorispresent..

Commented by Prithwish sen last updated on 03/Jul/19

yes your are right.

yesyourareright.

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