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Question Number 63564 by Tawa1 last updated on 05/Jul/19

Answered by MJS last updated on 05/Jul/19

$$\mathrm{the}\mathrm{flower}\mathrm{has}\mathrm{got}12\mathrm{arcs},\mathrm{each}\mathrm{one}\mathrm{of}\mathrm{length}$$$$\frac{1}{6}\times \mathrm{perimeter}\mathrm{of}\mathrm{the}\mathrm{circle}\Rightarrow$$$$p=12\times \frac{1}{6}\times 2\pi r=4\pi r$$$$r=10\Rightarrow p=40\pi$$

Commented by Tawa1 last updated on 05/Jul/19

$$\mathrm{God}\mathrm{bless}\mathrm{you}\mathrm{sir}$$

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