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Question Number 63750 by Tawa1 last updated on 08/Jul/19

Commented by Prithwish sen last updated on 08/Jul/19

perimeter of circle A = (2/3)πr unit  perimeter of circle B = 2πr unit  Circle A               covers (2/3)πr in 1 time  ∴ it covers 2πr in ((2πr)/((2/3)πr))  times = 3 times

perimeterofcircleA=23πrunitperimeterofcircleB=2πrunitCircleAcovers23πrin1timeitcovers2πrin2πr23πrtimes=3times

Commented by Tawa1 last updated on 08/Jul/19

God bless you sir

Godblessyousir

Answered by MJS last updated on 08/Jul/19

perimeter of circle A =p_A   perimeter of circle B=p_B   (r_B /r_A )=(p_B /p_A )=(3/1)=3  ⇒ answer (b)

perimeterofcircleA=pAperimeterofcircleB=pBrBrA=pBpA=31=3answer(b)

Commented by Tawa1 last updated on 08/Jul/19

God bless you sir, but i don′t understand how it is  (3/1)

Godblessyousir,butidontunderstandhowitis31

Commented by MJS last updated on 08/Jul/19

r_A =(r_B /3) ⇔ r_B =3r_A  ⇔ (r_B /r_A )=3  p_A =2πr_A =((2π)/3)r_B =(1/3)p_B  ⇔ (p_B /p_A )=3

rA=rB3rB=3rArBrA=3pA=2πrA=2π3rB=13pBpBpA=3

Commented by Tawa1 last updated on 08/Jul/19

I appreciate sir

Iappreciatesir

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