Question and Answers Forum

All Questions      Topic List

Others Questions

Previous in All Question      Next in All Question      

Previous in Others      Next in Others      

Question Number 63790 by rajesh4661kumar@gamil.com last updated on 09/Jul/19

Answered by Hope last updated on 10/Jul/19

a+b=6k  b+c=7k  c+a=8k  add them  2(a+b+c)=21k  a+b+c=((21k)/2)  a=((21k)/2)−7k=((7k)/2)  b=((21k)/2)−8k=((5k)/2)  c=((21k)/2)−6k=((9k)/2)  a:b:c=((7k)/2):((5k)/2):((9k)/2)=7:5:9

a+b=6kb+c=7kc+a=8kaddthem2(a+b+c)=21ka+b+c=21k2a=21k27k=7k2b=21k28k=5k2c=21k26k=9k2a:b:c=7k2:5k2:9k2=7:5:9

Answered by Hope last updated on 10/Jul/19

10^n −1=4707  10^n =4708=  n=log_(10) 4708

10n1=470710n=4708=n=log104708

Terms of Service

Privacy Policy

Contact: info@tinkutara.com