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Question Number 63834 by gunawan last updated on 10/Jul/19

$$\mathrm{The}14\mathrm{th}\mathrm{term}\mathrm{from}\mathrm{the}\mathrm{end}\mathrm{in}\mathrm{the}\mathrm{expansion}$$$$\mathrm{of}{(\sqrt{x}-\sqrt{y})}^{17}\mathrm{is}$$

Commented by kaivan.ahmadi last updated on 10/Jul/19

$$T_{14}=\left(\begin{array}{c}17\\ 13\end{array}\right){\left(\sqrt{x}\right)}^{17-13}{\left(\sqrt{y}\right)}^{13}$$

Commented by Prithwish sen last updated on 10/Jul/19

$$\mathrm{I}\mathrm{think}\mathrm{it}\mathrm{will}\mathrm{be}18-14+1=5^{\mathrm{th}}\mathrm{term}$$

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