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Question Number 63908 by gunawan last updated on 11/Jul/19

$$\mathrm{If}R={(5\sqrt{5}+11)}^{2n+1}=\left[R\right]+F,\mathrm{where}$$$$\left[R\right]\mathrm{denotes}\mathrm{the}\mathrm{greatest}\mathrm{integer}\mathrm{in}R,$$$$\mathrm{then}RF=2^{2n+1}.$$

Commented by gunawan last updated on 11/Jul/19

$$\mathrm{true}\mathrm{or}\mathrm{false}$$

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