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Question Number 63958 by meme last updated on 11/Jul/19

$$x^6-3x^5+4x^4-6x^3+5x^2-3x+2=0$$

Commented by Prithwish sen last updated on 11/Jul/19

$$(\mathrm{x}-1)({\mathrm{x}}^5-{2\mathrm{x}}^4+{2\mathrm{x}}^3-{4\mathrm{x}}^2+\mathrm{x}-2)=0$$$$(\mathrm{x}-1)\{{\mathrm{x}}^4(\mathrm{x}-2)+{2\mathrm{x}}^2(\mathrm{x}-2)+1(\mathrm{x}-2)\}=0$$$$(\mathrm{x}-1)(\mathrm{x}-2)({\mathrm{x}}^4+{2\mathrm{x}}^2+1)=0$$$$(\mathrm{x}-1)(\mathrm{x}-2){({\mathrm{x}}^2+1)}^2=0$$

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