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Question Number 64147 by aliesam last updated on 14/Jul/19

Answered by ajfour last updated on 14/Jul/19

=sin y−cos y+c

$$=\mathrm{sin}\:{y}−\mathrm{cos}\:{y}+{c} \\ $$

Answered by som(math1967) last updated on 14/Jul/19

∫((cos^2 y−sin^2 y)/(cosy−siny))dy  ∫(((cosy+siny)(cosy+siny))/((cosy−siny)))dy  ∫(cosy+siny)dy  siny−cosy+C

$$\int\frac{{cos}^{\mathrm{2}} {y}−{sin}^{\mathrm{2}} {y}}{{cosy}−{siny}}{dy} \\ $$$$\int\frac{\left({cosy}+{siny}\right)\left({cosy}+{siny}\right)}{\left({cosy}−{siny}\right)}{dy} \\ $$$$\int\left({cosy}+{siny}\right){dy} \\ $$$${siny}−{cosy}+{C} \\ $$

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