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Question Number 64186 by Hope last updated on 15/Jul/19
Answered by Hope last updated on 15/Jul/19
(2)2x+y+(2)2y+z+(2)2z+x⩾(2+2+2)22(x+y+z)do⩾9×22(x+y+z)2x+y+2y+z+2z+x⩾9x+y+zproved
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