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Question Number 64287 by aliesam last updated on 16/Jul/19

Commented by mathmax by abdo last updated on 16/Jul/19

$$R^{{}^{\prime }}\left(t\right)=\frac{15.0,01e^{-0,01t}(1+1,5e^{-0,01t})-15(1-e^{-0,01t})(-1,5)0,01e^{-0,01t}}{{(1+1,5e^{-0,01t})}^2}$$$$=\frac{0,15e^{-0,01t}(1+1,5e^{-0,01t})+0,15.1,5(1-e^{-0,01t})e^{-0,01t}}{{(1+1,5e^{-0,01t})}^2}$$$$=....$$

Commented by aliesam last updated on 16/Jul/19

$$thankyousir$$

Commented by mathmax by abdo last updated on 17/Jul/19

$$youarewelcome.$$

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