Two consecutive integers between which a root of the equation 1)x^3 +x−16=0 2) x^2 −3x+2=0 lies are;


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Question Number 64347 by Rio Michael last updated on 16/Jul/19

$T w o c o n s e c u t i v e i n t e g e r s b e t w e e n w h i c h a r o o t o f t h e e q u a t i o n$ $1) x^{3} + x - 16 = 0$ $2) x^{2} - 3 x + 2 = 0$ $l i e s a r e;$
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