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Question Number 64348 by Rio Michael last updated on 16/Jul/19

$$thevectors\mathit{a}and\mathit{b}aresuchthat\mid \mathit{a}\mid =3,\mid \mathit{b}\mid =5and\mathit{a}.\mathit{b}=-14$$$$find\mid \mathit{a}-\mathit{b}\mid$$

Answered by Tanmay chaudhury last updated on 17/Jul/19

$$\mid \mathit{a}-\mathit{b}{\mid }^2=(\mathit{a}-\mathit{b}).(\mathit{a}-\mathit{b})$$$$=\mathit{a}.\mathit{a}-2\mathit{a}.\mathit{b}+\mathit{b}.\mathit{b}$$$$=\mid \mathit{a}{\mid }^2-2\mathit{a}.\mathit{b}+\mid \mathit{b}{\mid }^2$$$$=9+28+25$$$$\mid \mathit{a}-\mathit{b}\mid =\sqrt{62}$$

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