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Question Number 64406 by rajesh4661kumar@gamil.com last updated on 17/Jul/19

Commented by Tony Lin last updated on 17/Jul/19

area of △=(1/2)∣ determinant (((x_2 −x_1 y_2 −y_1 )),((x_3 −x_1 y_3 −y_1 )))∣ =(1/2)∣ determinant ((x_1 ,y_1 ,1),((x_2 −x_1 ),(y_2 −y_1 ),0),((x_3 −x_1 ),(y_3 −y_1 ),0))∣ =(1/2)∣ determinant ((x_1 ,y_1 ,1),(x_2 ,y_2 ,1),(x_3 ,y_3 ,1))∣ =((√3)/4)a^2 so∣ determinant ((x_1 ,y_1 ,2),(x_2 ,y_2 ,2),(x_3 ,y_(3 ) ,2))∣ =3a^4

areaof△=12∣|x2−x1y2−y1x3−x1y3−y1|∣=12∣|x1y11x2−x1y2−y10x3−x1y3−y10|∣=12∣|x1y11x2y21x3y31|∣=34a2so∣|x1y12x2y22x3y32|∣=3a4

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