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Question Number 64688 by peter frank last updated on 20/Jul/19

	Answered by mr W last updated on 20/Jul/19

	$M_{0} = o r i g i n a l m a s s$ $- u \frac{d m}{d t} = m \frac{d v}{d t}$ $- u \int_{M_{0}}^{m} \frac{d m}{m} = \int_{v_{0}}^{v} d v$ $- u (\ln m - \ln M_{0}) = v - v_{0}$ $\Rightarrow v = v_{0} - u \ln \frac{m}{M_{0}}$ $w i t h m = \frac{M_{0}}{2}$ $\Rightarrow v = 20 - 5 \ln \frac{1}{2} = 23.47 m / s$
	Commented by peter frank last updated on 20/Jul/19

	$t h a n k y o u$
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