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Question Number 64730 by Tanmay chaudhury last updated on 20/Jul/19

Answered by ajfour last updated on 20/Jul/19

$$E=\rho j$$$$\Rightarrow E=\frac{\rho I}{2\pi r^2}$$$$△V=\int Eds=\frac{\rho I}{2\pi }(\frac{1}{D}-\frac{1}{D+w})$$$$i=\frac{△V}{R}=\frac{\rho Iw}{2\pi RD(D+w)}$$$$=\frac{250}{51}\approx 4.9A$$

Commented by Tanmay chaudhury last updated on 21/Jul/19

$$thankyousir$$

Answered by Tanmay chaudhury last updated on 21/Jul/19

Commented by Tanmay chaudhury last updated on 21/Jul/19

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