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Question Number 64730 by Tanmay chaudhury last updated on 20/Jul/19

Answered by ajfour last updated on 20/Jul/19

E=ρj  ⇒ E=((ρI)/(2πr^2 ))  △V =∫Eds = ((ρI)/(2π))((1/D)−(1/(D+w)))  i=((△V)/R)= ((ρIw)/(2πRD(D+w)))      =((250)/(51)) ≈ 4.9A

E=ρjE=ρI2πr2V=Eds=ρI2π(1D1D+w)i=VR=ρIw2πRD(D+w)=250514.9A

Commented by Tanmay chaudhury last updated on 21/Jul/19

thank you sir

thankyousir

Answered by Tanmay chaudhury last updated on 21/Jul/19

Commented by Tanmay chaudhury last updated on 21/Jul/19

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