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Question Number 64778 by aliesam last updated on 21/Jul/19

Commented by som(math1967) last updated on 21/Jul/19

$j o i n O, Q O, N O, M M, Q N, Q$ $n o w O N = N Q = O Q = O M = M Q$ $∴ ∠ N O M = 60 + 60 = 120 °$ $∠ M L N = \frac{1}{2} ∠ N O M = 60 °$ $∠ N K M = ∠ N O M = 120 ° [s u b t e n d o n s a m e s e g m e n t]$ $n o w e x t ∠ N K M = ∠ N L K + ∠ L N K$ $∴ ∠ L N K = 120 - 60 = 60$ $s o △ K L N e q u i l a t e r a l$
Commented by aliesam last updated on 21/Jul/19

$g o d b l e s s y o u$
	Answered by som(math1967) last updated on 21/Jul/19

	$△ K L N e q u i l a t e r a l$ $a r e a = \frac{\sqrt{3}}{4} \times 6^{2} = 9 \sqrt{3} s q u n i t$
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