Question Number 64867 by meme last updated on 22/Jul/19
$${x}^{\mathrm{4}} +\left(\mathrm{2}{i}−\mathrm{3}\right){x}^{\mathrm{3}} −\left(\mathrm{1}+\mathrm{6}{i}\right){x}^{\mathrm{2}} +\left(\mathrm{3}−\mathrm{2}{i}\right){x}−\mathrm{2}=\mathrm{0} \\ $$
Answered by MJS last updated on 22/Jul/19
$$\mathrm{no}\:``\mathrm{nice}''\:\mathrm{exact}\:\mathrm{solution} \\ $$$${x}_{\mathrm{1}} \approx−.\mathrm{809757}−.\mathrm{472644i}\approx.\mathrm{937603e}^{−\mathrm{2}.\mathrm{61325i}} \\ $$$${x}_{\mathrm{2}} \approx.\mathrm{245673}+.\mathrm{250694i}\approx.\mathrm{351002e}^{.\mathrm{795512i}} \\ $$$${x}_{\mathrm{3}} \approx.\mathrm{409313}−\mathrm{1}.\mathrm{88140i}\approx\mathrm{1}.\mathrm{92531e}^{−\mathrm{1}.\mathrm{35657i}} \\ $$$${x}_{\mathrm{4}} \approx\mathrm{3}.\mathrm{15477}+.\mathrm{103248i}\approx\mathrm{3}.\mathrm{15646e}^{.\mathrm{0327159i}} \\ $$