why do we divide each term by n when given the question lim


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Question Number 65013 by Rio Michael last updated on 24/Jul/19

$w h y d o w e d i v i d e e a c h t e r m b y n w h e n g i v e n t h e q u e s t i o n$ $\lim_{x \to \infty} \frac{3 + 2 n}{1 + n} ?$
	Answered by Tanmay chaudhury last updated on 24/Jul/19

	$\lim_{n \to \infty} \frac{\frac{3}{n} + 2}{\frac{1}{n} + 1}$ $= \frac{0 + 2}{0 + 1} = 2 [w e d e v i d e N_{r} a n d D_{r} b y h i g h e s t p o w e r$ $n t o g e t 0 (z e r o) b e c a u s e \frac{1}{\infty} \to 0]$
	Commented by Rio Michael last updated on 24/Jul/19

	$t h a n k s, a t t i m e s i j u s t t h i n k o f i n f i n i t y a s a n u m b e r$
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