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Question Number 65301 by LPM last updated on 28/Jul/19

Commented by MJS last updated on 28/Jul/19

$$\mathrm{I}\mathrm{think}\mathrm{it}\mathrm{should}\mathrm{ve}{a}^2+b^2=30\mathrm{because}\mathrm{then}$$$$\frac{ab}{3}=-3\mathrm{but}\mathrm{with}\mathrm{tbe}\mathrm{given}\mathrm{equations}\mathrm{we}\mathrm{get}$$$$\mathrm{values}\mathrm{different}\mathrm{from}\mathrm{each}\mathrm{other}$$

Answered by mr W last updated on 28/Jul/19

$$a-b=\pm 4\sqrt{3}$$$$a^2+a-(30\pm 4\sqrt{3})=0$$$$a=\frac{-1\pm \sqrt{121\pm 16\sqrt{3}}}{2}$$$$b=\frac{-1\pm (\sqrt{121\pm 16\sqrt{3}}\pm 8\sqrt{3})}{2}$$$$......$$

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