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Question Number 65959 by ajfour last updated on 06/Aug/19

x^5 +ax^3 +bx^2 +cx+d=0  (x^2 +px+q)(x^3 +rx^2 +sx+t)=0  then elimating r,s,t    pq(p^2 +a)+d=q(b+2pq)   q^2 (p^2 +a)+dp=q(c+q^2 )  please try bringing into single  variable sir...

$${x}^{\mathrm{5}} +{ax}^{\mathrm{3}} +{bx}^{\mathrm{2}} +{cx}+{d}=\mathrm{0} \\ $$$$\left({x}^{\mathrm{2}} +{px}+{q}\right)\left({x}^{\mathrm{3}} +{rx}^{\mathrm{2}} +{sx}+{t}\right)=\mathrm{0} \\ $$$${then}\:{elimating}\:{r},{s},{t}\: \\ $$$$\:{pq}\left({p}^{\mathrm{2}} +{a}\right)+{d}={q}\left({b}+\mathrm{2}{pq}\right) \\ $$$$\:{q}^{\mathrm{2}} \left({p}^{\mathrm{2}} +{a}\right)+{dp}={q}\left({c}+{q}^{\mathrm{2}} \right) \\ $$$${please}\:{try}\:{bringing}\:{into}\:{single} \\ $$$${variable}\:{sir}... \\ $$$$\: \\ $$

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