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Question Number 66108 by Rio Michael last updated on 09/Aug/19

Given that the binomial expansion of ((2 + kx)/((2−5x)^(2 ) )) , ∣x∣ < (2/(5 )) ,in ascending  powers of x is  (1/2) + (7/4)x + Ax^2  + ..., find the values of A and k

$${Given}\:{that}\:{the}\:{binomial}\:{expansion}\:{of}\:\frac{\mathrm{2}\:+\:{kx}}{\left(\mathrm{2}−\mathrm{5}{x}\right)^{\mathrm{2}\:} }\:,\:\mid{x}\mid\:<\:\frac{\mathrm{2}}{\mathrm{5}\:}\:,{in}\:{ascending} \\ $$ $${powers}\:{of}\:{x}\:{is}\:\:\frac{\mathrm{1}}{\mathrm{2}}\:+\:\frac{\mathrm{7}}{\mathrm{4}}{x}\:+\:{Ax}^{\mathrm{2}} \:+\:...,\:{find}\:{the}\:{values}\:{of}\:{A}\:{and}\:{k} \\ $$

Commented bymr W last updated on 09/Aug/19

sir, please change your style for your  posts such that they can be read   without horizontal scrolling. thanks!

$${sir},\:{please}\:{change}\:{your}\:{style}\:{for}\:{your} \\ $$ $${posts}\:{such}\:{that}\:{they}\:{can}\:{be}\:{read}\: \\ $$ $${without}\:{horizontal}\:{scrolling}.\:{thanks}! \\ $$

Commented bymr W last updated on 09/Aug/19

Commented bymr W last updated on 09/Aug/19

you can see the difference between  your post and my post.

$${you}\:{can}\:{see}\:{the}\:{difference}\:{between} \\ $$ $${your}\:{post}\:{and}\:{my}\:{post}. \\ $$

Commented byRio Michael last updated on 09/Aug/19

okay i′ll check it thanks

$${okay}\:{i}'{ll}\:{check}\:{it}\:{thanks} \\ $$ $$ \\ $$

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