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Question Number 66216 by Rio Michael last updated on 11/Aug/19

∣a ∣ = 3 ,∣b∣= 5 , a.b =−14 ∣a − b∣ = ?

∣a∣=3,∣b∣=5,a.b=−14∣a−b∣=?

Commented by Rasheed.Sindhi last updated on 11/Aug/19

∣a ∣ = 3 ,∣b∣= 5 ⇒a.b ≠−14 a.b=−15 or a.b=15

∣a∣=3,∣b∣=5⇒a.b≠−14a.b=−15ora.b=15

Commented by behi83417@gmail.com last updated on 11/Aug/19

∣a−b∣=(√(∣a∣^2 +∣b∣^2 +2∣a∣∣b∣cosθ))= =(√(3^2 +5^2 +2×(−14)))=(√(9+25−28))=(√6)

∣a−b∣=∣a∣2+∣b∣2+2∣a∣∣b∣cosθ==32+52+2×(−14)=9+25−28=6

Answered by Rasheed.Sindhi last updated on 11/Aug/19

∣a ∣ = 3 ,∣b∣= 5 , a.b =−15 ∣a − b∣ = ? ∣a∣ = 3⇒a=±3⇒b=∓5 [∵a.b=−15] ∣a − b∣=∣(±3)−(∓5)∣ =∣(±3)+(±5)∣ =∣±8∣=8

∣a∣=3,∣b∣=5,a.b=−15∣a−b∣=?∣a∣=3⇒a=±3⇒b=∓5[∵a.b=−15]∣a−b∣=∣(±3)−(∓5)∣=∣(±3)+(±5)∣=∣±8∣=8

Commented by Rio Michael last updated on 11/Aug/19

thanks

thanks

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