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Question Number 6630 by Tawakalitu. last updated on 06/Jul/16

A small source of sound emit energy uniformly in all   direction for a particular frequency, the intensity of sound   at a distane 2.0m from the source is 1.0 × 10^(−5)   and   corresponds to amplitude of oscillation on the air molecules  of  7u . assuming sound is propagated with any loss of energy  calculate:  (1) Intensity of sound  (2) the amplitude of oscillation of the air molecules  at a distance of  5.0m from the source.

$${A}\:{small}\:{source}\:{of}\:{sound}\:{emit}\:{energy}\:{uniformly}\:{in}\:{all}\: \\ $$$${direction}\:{for}\:{a}\:{particular}\:{frequency},\:{the}\:{intensity}\:{of}\:{sound}\: \\ $$$${at}\:{a}\:{distane}\:\mathrm{2}.\mathrm{0}{m}\:{from}\:{the}\:{source}\:{is}\:\mathrm{1}.\mathrm{0}\:×\:\mathrm{10}^{−\mathrm{5}} \:\:{and}\: \\ $$$${corresponds}\:{to}\:{amplitude}\:{of}\:{oscillation}\:{on}\:{the}\:{air}\:{molecules} \\ $$$${of}\:\:\mathrm{7}{u}\:.\:{assuming}\:{sound}\:{is}\:{propagated}\:{with}\:{any}\:{loss}\:{of}\:{energy} \\ $$$${calculate}: \\ $$$$\left(\mathrm{1}\right)\:{Intensity}\:{of}\:{sound} \\ $$$$\left(\mathrm{2}\right)\:{the}\:{amplitude}\:{of}\:{oscillation}\:{of}\:{the}\:{air}\:{molecules} \\ $$$${at}\:{a}\:{distance}\:{of}\:\:\mathrm{5}.\mathrm{0}{m}\:{from}\:{the}\:{source}. \\ $$

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