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Question Number 66399 by Rio Michael last updated on 14/Aug/19

Show that for all real  values of x;     x^(2/3)  + 6x^(1/3)  + 10 >0

$${Show}\:{that}\:{for}\:{all}\:{real} \\ $$ $${values}\:{of}\:{x};\: \\ $$ $$\:\:{x}^{\frac{\mathrm{2}}{\mathrm{3}}} \:+\:\mathrm{6}{x}^{\frac{\mathrm{1}}{\mathrm{3}}} \:+\:\mathrm{10}\:>\mathrm{0} \\ $$

Commented bykaivan.ahmadi last updated on 14/Aug/19

=(x^(1/3) +3)^2 +1>0

$$=\left({x}^{\frac{\mathrm{1}}{\mathrm{3}}} +\mathrm{3}\right)^{\mathrm{2}} +\mathrm{1}>\mathrm{0} \\ $$ $$ \\ $$

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