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Question Number 66431 by hmamarques1994@gmail.com last updated on 15/Aug/19

    Determine  x  e  y:       { ((x^(1/(√i)) + (1/y^(i(√i)) ) = 10)),(((1/((xy)^(i(√i)) )) = 21)) :}

Determinexey:{x1i+1yii=101(xy)ii=21

Answered by MJS last updated on 15/Aug/19

x^(1/(√i)) =x^(((√2)/2)−((√2)/2)i)   (1/y^(i(√i)) )=y^(((√2)/2)−((√2)/2)i)   a+b=10  ab=21  ⇒ a=3∧b=7 ∨ a=7∧b=3    we have to solve    z^(((√2)/2)−((√2)/2)i) =3 ⇒ z=3^((√2)/2) e^(i(((√2)ln 3)/2)) ≈1.55077+1.52444i    z^(((√2)/2)−((√2)/2)i) =7 ⇒ z=7^((√2)/2) e^(i(((√2)ln 7)/2)) ≈.766442+3.88400i                         ∨z=7^((√2)/2) e^(π(√2)) e^(i(((√2)(ln 7 −2π))/2)) ≈−335.646−25.1114i    solutions:    x=3^((√2)/2) e^(i(((√2)ln 3)/2)) ∧y=7^((√2)/2) e^(i(((√2)ln 7)/2))   x=3^((√2)/2) e^(i(((√2)ln 3)/2)) ∧y=7^((√2)/2) e^(π(√2)) e^(i(((√2)(ln 7 −2π))/2))   and exchange x⇄y

x1i=x2222i1yii=y2222ia+b=10ab=21a=3b=7a=7b=3wehavetosolvez2222i=3z=322ei2ln321.55077+1.52444iz2222i=7z=722ei2ln72.766442+3.88400iz=722eπ2ei2(ln72π)2335.64625.1114isolutions:x=322ei2ln32y=722ei2ln72x=322ei2ln32y=722eπ2ei2(ln72π)2andexchangexy

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