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Question Number 66478 by hmamarques1994@gmail.com last updated on 15/Aug/19

    lim_(x→2) [((log_x (2)−1)/(log_2 ((1/x))+1))]=?

limx2[logx(2)1log2(1x)+1]=?

Commented by gunawan last updated on 16/Aug/19

lim_(x→2) ((log_x 2−log_x x)/(log_2 ((1/x))+log_2 2))  =lim_(x→2) ((log_x ((2/x)))/(log_2 ((1/(2x)))))=((log_2 ((2/2)))/(log_2 ((1/4))))=((log_2 1)/(−2×log_2 ))=0

limx2logx2logxxlog2(1x)+log22=limx2logx(2x)log2(12x)=log2(22)log2(14)=log212×log2=0

Commented by Rasheed.Sindhi last updated on 16/Aug/19

log_2 ((1/x))+log_2 2=log_2 ((1/x)×2)=log_2 ((2/x))

log2(1x)+log22=log2(1x×2)=log2(2x)

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