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Question Number 66478 by hmamarques1994@gmail.com last updated on 15/Aug/19
limx→2[logx(2)−1log2(1x)+1]=?
Commented by gunawan last updated on 16/Aug/19
limx→2logx2−logxxlog2(1x)+log22=limx→2logx(2x)log2(12x)=log2(22)log2(14)=log21−2×log2=0
Commented by Rasheed.Sindhi last updated on 16/Aug/19
log2(1x)+log22=log2(1x×2)=log2(2x)
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