Question and Answers Forum

All Questions      Topic List

Limits Questions

Previous in All Question      Next in All Question      

Previous in Limits      Next in Limits      

Question Number 6668 by janzmir6996 last updated on 10/Jul/16

lim_(x→0) cos 2x/sin x2

$$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}cos}\:\mathrm{2}{x}/\mathrm{sin}\:{x}\mathrm{2} \\ $$

Commented by Rasheed Soomro last updated on 10/Jul/16

Do you mean    lim_(x→0)   cos 2x/sin x^2    ?

$${Do}\:{you}\:{mean}\:\:\:\:\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\:\mathrm{cos}\:\mathrm{2}{x}/\mathrm{sin}\:{x}^{\mathrm{2}} \:\:\:? \\ $$

Answered by FilupSmith last updated on 10/Jul/16

lim_(x→0)  ((cos 2x)/(sin x^2 )) = ((cos(0))/(sin(0^2 ))) = ∞

$$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{\mathrm{cos}\:\mathrm{2}{x}}{\mathrm{sin}\:{x}^{\mathrm{2}} }\:=\:\frac{\mathrm{cos}\left(\mathrm{0}\right)}{\mathrm{sin}\left(\mathrm{0}^{\mathrm{2}} \right)}\:=\:\infty \\ $$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com