Math Question and Answers


Question and Answers Forum

All Questions Topic List
None Questions
Previous in All Question Next in All Question
Previous in None Next in None
Question Number 66684 by Tinkutara@ last updated on 18/Aug/19

	Answered by MJS last updated on 18/Aug/19
	$this is old... you always say in words what you read and write down in numbers 1 one “1” = 1 1 two “1s” = 2 1 one “2” and one “1” = 1 2 1 1 and so on 1 1 1 2 2 1 3 1 2 2 1 1 1 3 1 1 2 2 2 1 1 1 1 3 2 1 3 2 1 1 ... you never get a “4” you can proof if a given “number” is correct or which had been the “input number” by going back uneven numbers digits can be input numbers only, i.e. a_n =13213 = one “3” and two “1s” and 3??? a_n =132131 is not correct, it must be 1351 a_n =1351 a_(n−1) =311111 but this isn′t correct too, it must be 51 ⇒ neithef 132131 nor 1351 are correct a_n =231231 a_(n−1) =332111 is not correct... but of course we can start with anything 1 2 3 x∉{1, 2, 3} 11 12 13 1x 21 1112 1113 111x 1211 3112 3113 311x 111221 132112 132113 13211x 312211 1113122112 1113122113 111312211x ... 4321 14131211 11141113111221 31143113312211 132114132123112221 1113122114111312111213213211 ... it has been explored by Goedel...$
	$this is old . . .$ $you always say in words what you read and$ $write down in numbers$ $1$ $one ‘ ‘ 1^{″} = 1 1$ $two ‘ ‘ {1 s}^{″} = 2 1$ $one ‘ ‘ 2^{″} and one ‘ ‘ 1^{″} = 1 2 1 1$ $and so on$ $1 1 1 2 2 1$ $3 1 2 2 1 1$ $1 3 1 1 2 2 2 1$ $1 1 1 3 2 1 3 2 1 1$ $. . .$ $you never get a ‘ ‘ 4^{″}$ $you can proof if a given ‘ ‘ {number}^{″} is correct$ $or which had been the ‘ ‘ input {number}^{″} by$ $going back$ $uneven numbers digits can be input numbers$ $only, i . e .$ $a_{n} = 13213 = one ‘ ‘ 3^{″} and two ‘ ‘ {1 s}^{″} and 3 ? ? ?$ $a_{n} = 132131 is not correct, it must be 1351$ $a_{n} = 1351$ $a_{n - 1} = 311111 but this {isn}^{'} t correct too, it$ $must be 51 \Rightarrow neithef 132131 nor 1351 are$ $correct$ $a_{n} = 231231$ $a_{n - 1} = 332111 is not correct . . .$ $but of course we can start with anything$ $1 2 3 x \notin {1, 2, 3}$ $11 12 13 1 x$ $21 1112 1113 111 x$ $1211 3112 3113 311 x$ $111221 132112 132113 13211 x$ $312211 1113122112 1113122113 111312211 x$ $. . .$ $4321$ $14131211$ $11141113111221$ $31143113312211$ $132114132123112221$ $1113122114111312111213213211$ $. . .$ $it has been explored by Goedel . . .$
	Commented by Tinkutara@ last updated on 18/Aug/19

	$W o n d e r f u l!$ $o l d i s g o l d :)$
Terms of Service
Privacy Policy
Contact: info@tinkutara.com

Question and Answers Forum