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Question Number 66718 by otchereabdullai@gmail.com last updated on 18/Aug/19

Commented by Tony Lin last updated on 19/Aug/19

Commented by Tony Lin last updated on 19/Aug/19
$2x(5−x)≤12 x(5−x)≤6 x^2 −5x+6≥0 (x−3)(x−2)≥0 ⇒x≥3 or x≤2 2x(5−x)≥8 x(5−x)≥4 x^2 −5x+4≤0 (x−1)(x−4)≤0 ⇒1≤x≤4 { ((x≥3 or x≤2)),((1≤x≤4)) :} ⇒1≤x≤2 or 3≤x≤4$
$2 x (5 - x) ⩽ 12$ $x (5 - x) ⩽ 6$ $x^{2} - 5 x + 6 ⩾ 0$ $(x - 3) (x - 2) ⩾ 0$ $\Rightarrow x ⩾ 3 o r x ⩽ 2$ $2 x (5 - x) ⩾ 8$ $x (5 - x) ⩾ 4$ $x^{2} - 5 x + 4 ⩽ 0$ $(x - 1) (x - 4) ⩽ 0$ $\Rightarrow 1 ⩽ x ⩽ 4$ ${\begin{cases} x ⩾ 3 o r x ⩽ 2 \\ 1 ⩽ x ⩽ 4 \end{cases}$ $\Rightarrow 1 ⩽ x ⩽ 2 o r 3 ⩽ x ⩽ 4$
Commented by otchereabdullai@gmail.com last updated on 19/Aug/19

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