Three school children share some oranges as follows: Akwasi gets (1/3) of the total and the remainder is shared between Abena and Juana in the ratio 2: 3 . If Abena gets 24 oranges , how many does Akwasi get.


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Question Number 67108 by otchereabdullai@gmail.com last updated on 22/Aug/19

$Three school children share some$ $oranges as follows : Akwasi gets \frac{1}{3} of$ $the total and the remainder is shared$ $between Abena and Juana in the ratio$ $2 : 3 . If Abena gets 24 oranges, how$ $many does Akwasi get .$
Commented by Prithwish sen last updated on 23/Aug/19

$Akwasi gets = (24 \times \frac{5}{2}) \times \frac{1}{2} = 30$
Commented by otchereabdullai@gmail.com last updated on 23/Aug/19

$thank you sir$
	Answered by Rasheed.Sindhi last updated on 23/Aug/19

	$N u m b e r o f o r a n g e s : n$ $A k w s s i g e t s \frac{n}{3}$ $R e m a i n i n g : n - \frac{n}{3} = \frac{2 n}{3}$ $A b e n a g e t s \frac{\frac{2 n}{3}}{5} \times 2, w h i c h i s e q u a l t o 24$ $\frac{\frac{2 n}{3}}{5} \times 2 = 24$ $\frac{2 n}{3} = 24 \times \frac{5}{2} = 60$ $\frac{n}{3} = \frac{60}{2} = 30$ $A k w a s i g e t s 30 o r a n g e s .$
	Commented by otchereabdullai@gmail.com last updated on 23/Aug/19

	$thank you sir$
	Answered by Rasheed.Sindhi last updated on 23/Aug/19

	$N u m b e r o f o r a n g e s : x$ $(\begin{matrix} A k w s i & A b e n a & J u a n a \\ R e m a i n i n g \times (2 / 5) & R e m a i n i n g \times (3 / 5 \\ x / 3 & (2 x / 3) \times (2 / 5) = 24 & (2 x / 3) \times (3 / 5) \end{matrix})$ $(2 x / 3) \times (2 / 5) = 24$ $x / 3 = \frac{24 \times (5 / 2)}{2} = \frac{60}{2} = 30$ $A k w a s i g e t s 30 o r a n g e s .$
	Commented by otchereabdullai@gmail.com last updated on 23/Aug/19

	$thank you sir$
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