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Question Number 67215 by Learner-123 last updated on 24/Aug/19

Commented by Learner-123 last updated on 24/Aug/19

  help me in Q.74.

helpmeinQ.74.

Answered by mr W last updated on 24/Aug/19

h=4m  s_1 =h+0.75h=1.75h  s_2 =0.75h+0.75^2 h=0.75×1.75h  ....  s=Σ_(n=1) ^∞ s_n =((1.75h)/(1−0.75))=7h=7×4=28m    t_1 =(√(h/(4.9)))+(√((0.75h)/(4.9)))=(1+(√(0.75)))(√(h/(4.9)))  t_2 =(√((0.75h)/(4.9)))+(√((0.75^2 h)/(4.9)))=(√(0.75))(1+(√(0.75)))(√(h/(4.9)))  ...  t=Σ_(n=1) ^∞ t_n =((1+(√(0.75)))/(1−(√(0.75))))×(√(h/(4.9)))=12.58 sec

h=4ms1=h+0.75h=1.75hs2=0.75h+0.752h=0.75×1.75h....s=n=1sn=1.75h10.75=7h=7×4=28mt1=h4.9+0.75h4.9=(1+0.75)h4.9t2=0.75h4.9+0.752h4.9=0.75(1+0.75)h4.9...t=n=1tn=1+0.7510.75×h4.9=12.58sec

Commented by Learner-123 last updated on 24/Aug/19

thanks sir.

thankssir.

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