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Question Number 67655 by ajfour last updated on 29/Aug/19

Commented by ajfour last updated on 29/Aug/19

$I f t h e m a n c a n p r o v i d e a m a x i m u m$ $a c c e l e r a t i o n a t o t h e b o x e s w h i l e$ $h e r u n s a l o n g, f i n d t h e f r i c t i o n$ $c o e f f i c i e n t o f h i s s h o e s w i t h$ $g r o u n d . (A s s u m e t h e g r o u n d h a s$ $t h e s a m e f r i c t i o n c o e f f i c i e n t$ $(s t a t i c o r k i n e t i c w i t h t h e b o x e s$ $a n d t h e {m a n}^{'} s s h o e s) .$
Commented by mr W last updated on 30/Aug/19

$F - μ (M + m) g = (M + m) a$ $μ m_{0} g - F = m_{0} a$ $\Rightarrow μ = \frac{(M + m + m_{0}) a}{(m_{0} - M - m) g} = \frac{\frac{m_{0}}{M + m} + 1}{\frac{m_{0}}{M + m} - 1} \times \frac{a}{g}$
Commented by ajfour last updated on 29/Aug/19

$V e r y p r e c i s e, a n d c o r r e c t, S i r .$ $t h a n k s!$
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