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Question Number 67708 by aliesam last updated on 30/Aug/19

Answered by mind is power last updated on 30/Aug/19

$$z=\frac{x}{y}$$$$y=\frac{x}{z}$$$$dy=-\frac{x}{z^2}dz$$$$\int -\frac{{xe}^z}{z^2}dz=x\int -\frac{e^z}{z^2}dz=x[\frac{e^z}{z}-\int \frac{e^z}{z}dz]$$$$=\frac{{xe}^z}{z}-x\int \frac{e^z}{z}dz$$$$=\frac{{xe}^z}{z}-xE\left(z\right)$$$$E\left(z\right)=exponontielintegral$$

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