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Question Number 67942 by mhmd last updated on 02/Sep/19

∫e^(y^2 /2)   dy

ey2/2dy

Commented by mr W last updated on 09/Feb/21

∫e^(y^2 /2) dy=(√(π/2)) erfi((y/( (√2))))+C  ∫e^(−(y^2 /2)) dy=(√(π/2)) erf((y/( (√2))))+C  erf(), erfi() = error functions

ey22dy=π2erfi(y2)+Cey22dy=π2erf(y2)+Cerf(),erfi()=errorfunctions

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