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Question Number 68473 by naka3546 last updated on 11/Sep/19
sin72°sin42°=ptan12°=?
Commented by Kunal12588 last updated on 11/Sep/19
sin(60°+12°)sin(30°+12°)=p⇒32cos12°+12sin12°12cos12°+32sin12°=p⇒3+tan12°1+3tan12°=p⇒tan12°(1−p3)=p−3⇒tan12°=p−31−p3
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