Question and Answers Forum

All Questions      Topic List

Geometry Questions

Previous in All Question      Next in All Question      

Previous in Geometry      Next in Geometry      

Question Number 68503 by TawaTawa last updated on 12/Sep/19

Commented by Prithwish sen last updated on 12/Sep/19

2x((π6^2 )/4) −2[36((π/3)−((√3)/4))]=18[(√3)−(π/3)] ∽ 12.33 please check.

$$\mathrm{2x}\frac{\pi\mathrm{6}^{\mathrm{2}} }{\mathrm{4}}\:−\mathrm{2}\left[\mathrm{36}\left(\frac{\pi}{\mathrm{3}}−\frac{\sqrt{\mathrm{3}}}{\mathrm{4}}\right)\right]=\mathrm{18}\left[\sqrt{\mathrm{3}}−\frac{\pi}{\mathrm{3}}\right]\:\backsim\:\mathrm{12}.\mathrm{33} \\ $$$$\boldsymbol{\mathrm{please}}\:\boldsymbol{\mathrm{check}}. \\ $$

Commented by TawaTawa last updated on 12/Sep/19

I don′t know the answer, but please help me explain more. God bless you sir

$$\mathrm{I}\:\mathrm{don}'\mathrm{t}\:\mathrm{know}\:\mathrm{the}\:\mathrm{answer},\:\mathrm{but}\:\mathrm{please}\:\mathrm{help}\:\mathrm{me}\:\mathrm{explain}\:\mathrm{more}.\:\mathrm{God}\:\mathrm{bless} \\ $$$$\mathrm{you}\:\mathrm{sir} \\ $$

Commented by mr W last updated on 12/Sep/19

2[(1/2)×(π/6)×6^2 −(6^2 /2)((π/3)−sin (π/3))] =6(3(√3)−π)

$$\mathrm{2}\left[\frac{\mathrm{1}}{\mathrm{2}}×\frac{\pi}{\mathrm{6}}×\mathrm{6}^{\mathrm{2}} −\frac{\mathrm{6}^{\mathrm{2}} }{\mathrm{2}}\left(\frac{\pi}{\mathrm{3}}−\mathrm{sin}\:\frac{\pi}{\mathrm{3}}\right)\right] \\ $$$$=\mathrm{6}\left(\mathrm{3}\sqrt{\mathrm{3}}−\pi\right) \\ $$

Commented by TawaTawa last updated on 13/Sep/19

Sir, is it area of the square minus area of the two quarter circle ?

$$\mathrm{Sir},\:\mathrm{is}\:\mathrm{it}\:\mathrm{area}\:\mathrm{of}\:\mathrm{the}\:\mathrm{square}\:\mathrm{minus}\:\mathrm{area}\:\mathrm{of}\:\mathrm{the}\:\mathrm{two}\:\mathrm{quarter}\:\mathrm{circle}\:? \\ $$

Commented by TawaTawa last updated on 13/Sep/19

Or please sir help me label the diagram

$$\mathrm{Or}\:\mathrm{please}\:\mathrm{sir}\:\mathrm{help}\:\mathrm{me}\:\mathrm{label}\:\mathrm{the}\:\mathrm{diagram} \\ $$

Commented by mr W last updated on 13/Sep/19

Commented by mr W last updated on 13/Sep/19

area of (π/6)−sector =(6^2 /2)((π/6)) area of green segment=(6^2 /2)((π/3)−sin (π/3))

$${area}\:{of}\:\frac{\pi}{\mathrm{6}}−{sector}\:=\frac{\mathrm{6}^{\mathrm{2}} }{\mathrm{2}}\left(\frac{\pi}{\mathrm{6}}\right) \\ $$$${area}\:{of}\:{green}\:{segment}=\frac{\mathrm{6}^{\mathrm{2}} }{\mathrm{2}}\left(\frac{\pi}{\mathrm{3}}−\mathrm{sin}\:\frac{\pi}{\mathrm{3}}\right) \\ $$

Commented by TawaTawa last updated on 13/Sep/19

God bless you sir.

$$\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir}. \\ $$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com