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Question Number 68515 by azizullah last updated on 12/Sep/19

Commented by Prithwish sen last updated on 13/Sep/19

$${\left[\mathrm{z}(\mathrm{z}-6)\right]}^2={\left[(3+2\mathrm{i})(3+2\mathrm{i}-6)\right]}^2={[{\left(2\mathrm{i}\right)}^2-{\left(3\right)}^2]}^2$$$$={(-13)}^2=169$$

Commented by azizullah last updated on 13/Sep/19

$$\mathrm{thanks}$$

Answered by Rasheed.Sindhi last updated on 12/Sep/19

$$={\mathrm{z}}^2({\mathrm{z}}^2-12\mathrm{z}+36)$$$$={(3+2\mathrm{i})}^2({(3+2\mathrm{i})}^2-12(3+2\mathrm{i})+36)$$$$=(9-4+12\mathrm{i})(9-4+12\mathrm{i}-36-24\mathrm{i}+36)$$$$=(5+12\mathrm{i})(5+12\mathrm{i}-24\mathrm{i})$$$$=(5+12\mathrm{i})(5-12\mathrm{i})$$$$={\left(5\right)}^2-{\left(12\mathrm{i}\right)}^2$$$$=25+144=169$$

Commented by azizullah last updated on 13/Sep/19

$$\mathbf{sir}!\mathbf{thanks}\mathbf{of}\mathbf{good}\mathbf{work}.$$

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