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Question Number 68609 by TawaTawa last updated on 14/Sep/19

Commented by TawaTawa last updated on 14/Sep/19

$$\mathrm{I}\mathrm{got}4\mathrm{m}/{\mathrm{s}}^2\mathrm{in}\mathrm{number}14,\mathrm{please}\mathrm{help}\mathrm{me}\mathrm{check}$$

Answered by mr W last updated on 14/Sep/19

$$\left(13\right)$$$$s=t^3-t^2-t-2$$$$v=\frac{ds}{dt}=3t^2-2t-1$$$$a=\frac{dv}{dt}=6t-2$$$$a_{ave}=\frac{{\int }_2^{4}a\left(t\right)dt}{4-2}=\frac{{[3t^2-2t]}_2^4}{2}=\frac{32}{2}=16m/s^2$$$$or$$$$a\left(4\right)=6\times 4-2=22$$$$a\left(2\right)=6\times 2-2=10$$$$a_{ave}=\frac{22+10}{2}=16m/s^2$$$$$$$$\left(14\right)$$$$3t^2-2t-1=0$$$$(3t+1)(t-1)=0$$$$\Rightarrow t=1$$$$a\left(1\right)=6\times 1-2=4m/s^2$$

Commented by TawaTawa last updated on 14/Sep/19

$$\mathrm{God}\mathrm{bless}\mathrm{you}\mathrm{sir},\mathrm{i}\mathrm{appreciate}$$

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