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Question Number 68629 by TawaTawa last updated on 14/Sep/19

Answered by $@ty@m123 last updated on 14/Sep/19

$$\mathrm{\angle }XYT=\mathrm{\angle }XTP$$$$\Rightarrow \mathrm{\angle }XYT={50}^{\mathrm{o}}$$$$\mathrm{L}et\mathrm{\angle }YXT=\mathrm{\angle }XTY=x$$$$\Rightarrow x+x+{50}^{\mathrm{o}}={180}^{\mathrm{o}}$$$$\Rightarrow x=\frac{130}{2}$$$$\Rightarrow \mathrm{\angle }YXT={50}^{\mathrm{o}}$$$$\Rightarrow \mathrm{\angle }TZY={50}^{\mathrm{o}}$$

Commented by TawaTawa last updated on 17/Sep/19

$$\mathrm{God}\mathrm{bless}\mathrm{you}\mathrm{sir}$$

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