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Question Number 68714 by Learner-123 last updated on 15/Sep/19

Answered by mr W last updated on 15/Sep/19

$$accelerationofobjectC=\frac{1.2}{2}=0.6m/s^2$$$$forceincable=\frac{1}{2}\times 375\times \frac{10+0.6}{10}=198.75N$$$$powerinput=\frac{198.75\times 0.6}{0.85}=140.3watt$$

Commented by Learner-123 last updated on 15/Sep/19

$$pleaseelaborate‘‘forcein{cable}^{″}.$$

Commented by mr W last updated on 16/Sep/19

$$weightofobject=375N$$$$massofobject=\frac{375}{g}=37.5kg$$$$letforceincable=T$$$$2T-mg=ma$$$$\Rightarrow T=\frac{m(g+a)}{2}=\frac{375(10+0.6)}{2\times 10}=198.75N$$

Commented by Learner-123 last updated on 18/Sep/19

$$thankssir.$$

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